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Topic: **Rounding numbers homework****Question:**
How do I find out 1/4 (1 quarter) of 9/10 (nine tenths)? I need to know how to do others, so can someone show me an really easy method with the solution?
Thanks guys, but I don't know how to make 25% of 9/10 either!! Maths is always difficult for me!!
Message for Spencer - thanks for working that out. I understand all of it apart from the answer. lol. I divided 40 by 9 and I got 4.4. I have to round it up/down to the nearest number, so I'm getting 4. How did you get your answer?

July 22, 2019 / By Genna

When looking for a fraction of a fraction, all that you have to do is multiply the fractions together. So, the equation to solve 1/4th of 9/10ths is simply (1/4)(9/10). The numeration, the top of the fraction is equal to 9*1, and the denominator is equal to 4*10. So, the new fraction is (9*1)/(4*10). This can be simplified to 9/40ths. This could be your final answer, unless you want a decimal answer. In that case you simply need to divide 9 by 40 on a calculator, which gives you a final answer of .225. Here are the steps one by one, 1/4 * 9/10 = (1*9) / (4*10) = 9/40 = .225 Hope I was helpful B)

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Did you like the answer? We found more questions related to the topic: **Rounding numbers homework**

Percentage of women who complete the marathon = 18/25 * 100% = 72% Percentage of men who complete the marathon = 21/35 * 100% = 60% Did not complete = [25+35] - [ (25-18) + (35 - 21) ] . . . . . . . . . . . . . . = 60 - (7 + 14) . . . . . . . . . . . . . . = 60 - 21 . . . . . . . . . . . . . . = 39 . . . . . . . . . . . . . . = 39/60 * 100% . . . . . . . . . . . . . . = 65%

Women Completed, 60% Men Completed, 72% Not Completed, 65% I Believe I enjoy math so I hope this helped, Good Luck.

1/4 of 9/10 equals 1/4 x 9/10 multiple top together and multiple bottom together (1x9) / (4x10) = 9/40 Check If I add all the quarters, then it should equal to 9/10 9/40 + 9/40 + 9/40 + 9/40 = (9+9+9+9)/40 = 36/40 = 9/10 Check Answer is 9/40

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1) 2sin3x+1=0 2sin3x= -1 sin3x=-(1/2) now print out the unit circle, take a look to find where on it sinθ=-(1/2) θ is in Quadrant III and IV and=[7π/6 and 11π/6] 2x=7π/6 since the period of a sine curve=2π, we add k*2π to it 2x= 7π/6+k*2π or x= 7π/12+(k*2π/2)= 7π/12+kπ next angle 2x=11π/6 +k*2π x= 11π/12+ kπ the trick here is you let θ=2x, and solve for θ, then replace θ=2x, and solve for x this method is called subtitution and been used very so often every where. 2)3cos2x+1=0 cos 2x= -1/3 if cosθ= -1/3 then θ is in QII, and III find cosθ=-1/3 by finding cosß=1/3 ß=70.53º ß+θ=180º ==> θ=180- 70.53=109.47º 2x=109.47 x=109.47/2=54.74º next angle θ=360- 109.47=250.53º x=125.265º in order for you to understand it, you need to understand your unit circle., and how to read your angle on the graph of the unit circle. 3)4tan2x+10=0 4tan2x=-10 tan2x=-10/4=-5/2 since tanx=sinx/cosx tanx is negative when sinx and cosx have different signs. therefore, x is in QII and IV, this is important, because it tells you what angle it is from 0º to 360º let tanθ=5/2 θ=68.19º in QI to find the angle in QIV =360º- 68.19º=291.81º=2x x=145.91º next angle in QII= 180º- 68.19º=111.81º trick is to let θ=2x or 3x or whatever, and to find angle θ in QI then find the angle that fits your problem. still, you need to know the unit circle.

i'm working in this too. to discover the cordanates, stick to this occasion: For #a million: you could take the 1st y (10) and plug it in to the 2nd problem (it could appear like: 10=5x+20) and artwork it out from there.

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