5150 Shares

# How do you balance this equation?

June 25, 2019 / By Audra
Question: PO₄ + H₂O → H₃PO₄ This problem was on a recent homework assignment in my chemistry class, and NO ONE could figure it out. We're only in 8th grade Honors science, so no answers that are super-complicated, if possible. And if you don't know how to type subscripts you can just copy-paste, or just use the regular number, I'll understand.

## Best Answers: How do you balance this equation?

Abbey | 6 days ago
This not a chemistry equation nor a math question. As it is, it cannot be balanced chemically PO4 is a radical and should be written as PO4^3-.. You can end up with something that is balanced , but it is not chemistry PO4. + H2O --> H3PO4 To balance the hydrogen you have to multply the water by three and the H3PO4 by two: . Like so: 3H2O 2H3PO4 The PO4 would have to have a 2 to give you 2 PO4 + 3H2O --> 2 H3PO4. you can add 3 O.(ugh) Try these for practice: NaOH + H2SO4 --> Na2SO4 + H2O, and AgNO3 + CaCl2 --> AgCl + Ca(NO3)2
👍 140 | 👎 6
Did you like the answer? How do you balance this equation? Share with your friends

We found more questions related to the topic: Third grade homework assignments

You wrote, "Cu(NO3)2 (aq) + NH4OH (aq) -----> CuOH (s) NH4(NO3)2 (aq)" This equation is a nonstarter. The equation should look like this:: Cu(NO3)2(aq) + 2NH4OH(aq) ---> Cu(OH)2(s) + 2NH4NO3(aq) There is no CuOH formed and there is no such compound as NH4(NO3)2. The next problem is that there is no NH4OH. What we call ammonium hydroxide is actuall ammonia (NH3) dissolved in water. A more accurate equation will look like this: Cu(NO3)2(aq) + 2NH3(aq) + 2H2O(l) ---> Cu(OH)2(s) + 2NH4NO3(aq) The net ionic equation for the first version... Cu(NO3)2(aq) + 2NH4OH(aq) ---> Cu(OH)2(s) + 2NH4NO3(aq) ... the net ionic equation is: Cu2+ + 2OH- --> Cu(OH)2(s) ...... NH4+ and NO3- are spectator ions For the more accurate equation the net ionic equation is: Cu2+ + 2NH3(aq) + 2H2O(l) ---> Cu(OH)2(s) + 2NH4+ ============ Follow up ============== With all due respect, you do NOT have it written correctly, and neither gp4rts nor Stefany know what they are talking about. As I said above, "There is no CuOH formed and there is no such compound as NH4(NO3)2." =========== More follow up ============ For one thing, you need to pay attention to the oxidation numbers of the elements and polyatomic ions that you are putting together to form the formula of the products. For instance, in double replacement reactions there are no oxidation numbers changes (redox), so be sure adjust the subscripts so that the sum of the oxidation numbers is zero. Cu == +2 and OH == -1. Therefore, you need two OH- for each Cu.... Cu(OH)2.... +2 + 2(-1) = 0 NH4 == +1, NO3 == -1. They combine in a 1:1 ratio to give an oxidation number sum of zero. Don't bring the subscripts to the products from the reactants. The subscripts of the products must be determined from the oxidation numbers of the species you are combining. Water is often a product in acid/base reactions. It is also formed when carbonates or bicarbonates react with acids. Water will always be a product in the complete combustion of a hydrocarbon. Acid/base: 2HC2H2O2(aq) + Ca(OH)2(s) --> Ca(C2H2O2)2(aq) + 2H2O(l) Acid/carbonate: HCl(aq) + NaHCO3(s) --> NaCl(aq) + CO2(g) + H2O(l) Combustion: C5H12(g) + 8O2(g) --> 5CO2(g) + 6H2O(l) Using a solubility table is a **good** thing. Continue to include the state symbols in the equation. It will give you a better idea of how all this stuff looks, like what is dissolved in water, what is precipitating out, and what just wandered off as a gas. I require my students to include state symbols when they write chemical equations and particularly when they are predicting the products.
You have written it correctly but the formula is incorrect. The formula for copper hydroxide is Cu(OH)2 and for ammonium nitrate NH4NO3 , so the reaction should be Cu(NO3)2(aq) + 2NH4OH(aq) ---------> Cu(OH)2 + 2NH4NO3(aq)