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Three times the square of a number decreased by eight times the number is three. What is the number?

Three times the square of a number decreased by eight times the number is three. What is the number? Topic: How to write a squared number
June 16, 2019 / By Kelan
Question: Three times the square of a number decreased by eight times the number is three. What is the number? How do you find the number?
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Best Answers: Three times the square of a number decreased by eight times the number is three. What is the number?

Herb Herb | 1 day ago
Write the information in the form of an equation: Let the number be x Three times the square of a number = 3x^2 8 times the number = 8x Three times the square of a number decreased by eight times the number is three => 3x^2-8x=3 Rearrange this into the form: 3x^2-8x-3=0 Now you can factorise this and solve it to get the two possibilities for x
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We found more questions related to the topic: How to write a squared number


Herb Originally Answered: POW # 10 Guess my number I am a 4-digit number. My tens digit is 3 times my ones digit and my hundredths digi?
this question is whack, but all you have to work with is multiples of 3 so if you meant TENTHS: 93.13 93.26 93.39 31.13 31.26 31.39 62.13 62.26 62.39 now if you meant tens after all- then 93.39 31.13 62.26 see the pattern? and finally, with your hundredths digit being 3 more than tens (which all other answerers seemed to have failed to double check), I think there is only one answer! 93.26
Herb Originally Answered: POW # 10 Guess my number I am a 4-digit number. My tens digit is 3 times my ones digit and my hundredths digi?
First, create equations: x = the tens digit, y = those digit. you recognize right here: x + y = 7 and x = 3y - a million Plug the 2d equation into the 1st: (3y - a million) + y = 7 3y - a million + y = 7 4y - a million = 7 4y = 8 y = 2 considering the fact that x + y = 7, you recognize that x = 7 - y = 7 - 2 = 5. So, the variety is fifty two

Elkanah Elkanah
Let the number be x. Three times the square of a number decreased by eight times the number is three. Putting that in terms of x: 3x² - 8x = 3 or 3x² - 8x - 3 = 0 3x² - 9x + x - 3 = 0 3x.(x - 3) + 1.(x - 3) = 0 (3x + 1).(x - 3) = 0 x = 3 or -1/3
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Cheyenne Cheyenne
locate the huge type such that? a. its sq. is 12 greater beneficial than the huge type.is 4 the place 4^2 = 4 + 12 b. its sq. decreased with the help of thrice the huge type is eighteen is 6 the place 6^2 -- 3(6) = 18. c. the made of the huge type and four below the huge type 32 is 8 the place 8*(8 -- 4) = 32. d. the sq. of one greater beneficial than the huge type is 4 greater beneficial than 4 instances the huge type is 4 the place (4 + one million)^2 = 4(4) + 4. e. its sq. greater beneficial with the help of 8 instances the huge type is -15 is --3 the place (--3)^2 + 8(--3) = -- 15..
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Cheyenne Originally Answered: Using a balance scale, what's the least number of times you need to use it in order to find the "false" coin?
If you are lucky, the least number of times would be ONE (if by chance you select the non-gold coin to compare with a gold coin, you will know immediately which one is lighter). I think your question wants to know the MAXIMUM number of times you would need to use the scale; in that case it would be FOUR (if by chance the first four pairs of coins you pick up and measure happen to be the 8 gold coins, which would obviously balance out) - which means the leftover coin would HAVE to be the non-gold one, no weighing necessary :)

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